What Mass Of Glucose Should Be Dissolved

How many meters of glucose (C6H12O6) must be dissolved in 10.0 kg of water to get solution with freezing point of 4.2 C? 3

The equation is dT = Kfm.

Kf is the specific constant of water solution Kf is equal to 1.86.

m molarity is m = ■■■■■ / kg solvent of solution

dT, temperature change is basically the freezing point.

By entering a specific quote, you will get:

4.2 = 1.86 meters

m = ....... (value)

From the molarity equation, you know that

m = kg of soluble ■■■■■ / solvent

Water is its solution. You dissolve glucose in it.

Replace the value of m you get in the equation with the kilogram of water you get.

Find the solution (glucose). With the glucose formula, you can calculate the molarity of finding m for glucose.

(0 (4.2)) ° C / (1.86 ° C / m) = 2,258 m

(2.258 mol / kg) x (10.0 kg) x (180.1559 g C6H12O6 / mol) = 4068 g = 4.0 kg C6H12O6